Question 987137
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{{{y=x^2-10}}}
{{{y+10=x^2}}} Use this to substitute for x^2.
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{{{9x^2-y^2=90}}} Substitute for x^2.
{{{9(y+10)-y^2=90}}}
{{{9y+90-y^2=90}}}
{{{9y-y^2=0}}}
{{{y(9-y)=0}}}
{{{y=0}}} {{{OR}}} {{{9-y=0}}}
{{{y=0}}} {{{OR}}} {{{9=y}}}
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For y=0:
{{{y=x^2-10}}}
{{{0=x^2-10}}}
{{{10=x^2}}}
{{{sqrt(10)=x}}}
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ANSWER 1: ({{{(plus_or_minus) sqrt(10)}}},{{{0)}}})
For other answers, substitute 9 the same way.