Question 987072

A box contains 10 two-inch screws, of which 4 have a Phillips head and 6 have a regular head. Suppose that you select 3 screws randomly from the box. What is the probability that there will be more than one phillips head screw in a with replacement scenario?

Please help me out
<pre>Total screws: 10
Total Philips screws: 4
Total regular screws: 6
P(1 Philips screw) = {{{4/10}}}, or {{{2/5}}}

With replacement, 
P(2 Philips screws) = {{{(2/5) * (2/5)}}}, or {{{(2/5)^2}}}, or {{{4/25}}}

With replacement, 
P(3 Philips screws) = {{{(2/5) * (2/5) * (2/5)}}}, or {{{(2/5)^3}}}, or {{{8/125}}}
The probability that you will get MORE THAN 1 (meaning 2 or 3 Philips screws) = P(2P or 3P), or {{{4/25 + 8/125}}}, or {{{20/125 + 8/125}}}, or {{{highlight_green(28/125)}}}