Question 987096
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{{{f(x)}}} = {{{(x^2 - x - 6)/(x - 3)}}} =           -----> (factorize the numerator) -----> 


= {{{((x+2)*(x-3))/(x-3)}}} = {{{x + 2}}}. 


At  x=3  you  have   x+2 = 5.


So,  define   f(3) = 5,  and you will have the continuous function.