Question 986937
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Notice that  1.125 = {{{9/8}}}.


Hence,  {{{log(10, (1.125))}}} = {{{log(10, (9/8))}}} = {{{log(10, 9)}}} - {{{log(10,8)}}} = {{{2log(10,3)}}} - {{{3log(10,2)}}} = 2*0.4771 - 3*0.3010 = 0.0512.