Question 986884
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I suspect what you did was forget to put in a zero place holder for a missing term when you did your synthetic division.  If you did:
<pre>
  1  |  1   1   -2
            1    2
     --------------
        1   2    0
</pre>
and then interpreted the result as *[tex \Large x^2\ +\ 2], you would get the result you reported.  Try this:
<pre>

  1  |  1   1   0  -2
            1   2   2
     ----------------
        1   2   2   0
</pre>
which result would be interpreted as *[tex \Large x^2\ +\ 2x\ +\ 2].  Let me know how that works for you.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it

*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \