Question 986789
What are the steps I should take to solve for x in this trigonometric equation?

{{{ cos^2(x)-sin^2(x)=sin(x) }}}
<pre>{{{cos^2(x) + sin^2(x) = 1}}} --------> {{{cos^2(x) = 1 - sin^2(x)}}}
{{{1 - sin^2(x) - sin^2(x) = sin x}}} -------- Substituting {{{1 - sin^2(x)}}} for {{{cos^2(x)}}}
{{{2sin^2(x) + sin x - 1 = 0}}}
{{{(2sin x - 1)(sin x + 2) = 0}}}
{{{sin x = 1/2}}}            OR           {{{sin x = - 2}}} (ignore)
{{{x = sin^(-1) (1/2)}}}, and {{{highlight_green(system(x = 30^o_or,x = 150^o))}}}