Question 986740
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In order for *[tex \Large ax^2\ +\ bx\ +\ c] to have one zero with a multiplicity of two, the discriminant, *[tex \Large b^2\ -\ 4ac] must be equal to zero.  So solve *[tex \Large B^2\ -\ 48\ =\ 0]


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it

*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \