Question 986704
Find the original position of the ladder.
Distance from wall to ladder : {{{d[x]=5cos(70)=1.710}}}{{{m}}}
Distance from floor to ladder : {{{d[y]=5sin(70)=4.698}}}{{{m}}}
So the new position is,
{{{d[y]=4.698-2=2.698}}}
{{{5sin(theta)=2.698}}}
{{{sin(theta)=0.53969}}}
{{{theta=32.7}}}
The new position from the wall is,
{{{d[x]=5cos(32.7)=4.209}}}{{{m}}}
So the difference in x position is,
{{{DELTA=4.209-1.710}}}
{{{DELTA=2.499}}}{{{m}}}
or {{{2.5}}}{{{m}}}