Question 986710

The number of elements in {{{H}}} is four times that in {{{G}}}; so, {{{H=4G}}}

 If {{{n(U)=60 }}}, then {{{H+G=60}}}

since {{{H=4G}}}, we have {{{4G+G=60}}}=>{{{5G=60}}}=>{{{G=60/5}}}=>{{{G=12}}}

then {{{H=4*12}}}=>{{{H=48}}}