Question 986687
Hi there,
y = (x^2 - 3)(x + 3)
y = x^3 + 3x^2 - 3x - 9
Differentiate:
dy/dx = 3x^2 + 6x - 3
Substitute x = 2
= 3(2)^2 + 6(2) - 3
= 12 + 12 - 3
= 21
Gradient of tangent = 21
Hope this helps :-)