<PRE><B>Question 986656</B>
In my Geometry Book it says line GH has endpoints G(-3,2) and H(3,-2) 
The question says find GH to the nearest tenth?
-----
Formula for distance:: D = sqrt[(change in x)^2+(change in y)^2]
-----
Your Problem:
-----
D = sqrt[(3--3)^2 +(2--2)^2]
-----
D = sqrt[6^2 + 4^2]
-----
D = sqrt(36+16)
----
D = sqrt(52)
-----
D = sqrt(4*13)
-----
D = 2sqrt(13)
----------------
Cheers,
stan H.
------------</PRE>