Question 986567
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The intercepts of any line, presuming the line is other than horizontal or vertical such that it has both *[tex \Large x] and *[tex \Large y] intercepts are two points:  the *[tex \Large x]-intercept is of the form *[tex \Large (a,0)] and the *[tex \Large y]-intercept is of the form *[tex \Large (0,b)].


Because the coefficients on your variables are both non-zero, you are guaranteed to have a line that intersects both axes.  All that is left for you to do is to find the two intercept points by finding the values of *[tex \Large a] (so that you can create the point *[tex \Large (a,0)] ) and *[tex \Large b] (so that you can create the point *[tex \Large (0,b)]).


To find the value *[tex \Large a], substitute zero for *[tex \Large y] in your equation and then solve for *[tex \Large x].  The value of *[tex \Large x] when *[tex \Large y] is zero is the value *[tex \Large a] that you need for your *[tex \Large x]-intercept.


Likewise, to find the value of *[tex \Large b], substitute zero for *[tex \Large x] and then solve for *[tex \Large y]


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it

*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \