Question 84333
write the Quadratic equation that goes through the points (0,12),(4,0) and(-3,0)
A factorable quadratic equation has this form:
{{{y=a(x-b)(x-c)}}}
-b and -c equal the x intercepts
{{{y=a(x-4)(x+3)}}}*
let x be 0 and y be 12 and solve for a
{{{12=a(0-4)(0+3)}}}
{{{12=a(-4)(3)}}}
{{{12=-12a}}}
{{{12/-12=-12a/-12}}}
{{{-1=a}}}
Let a=-1 in *
{{{y=-(x-4)(x+3)}}}
Happy Calculating!!!!