Question 986431
{{{q(x) = 1/(x^2 -9)}}} 


{{{q(y + 3)}}}=?


{{{q(y + 3) = 1/((y+3)^2 -9)}}}


{{{q(y + 3) = 1/((y^2+6y+9) -9)}}}


{{{q(y + 3) = 1/(y^2+6y+9 -9)}}}


{{{q(y + 3) = 1/(y^2+6y)}}}


{{{q(y + 3) = 1/(y(y+6))}}}