Question 986481
<font face="Times New Roman" size="+2">


You can't prove that B is the midpoint of AC.  Consider the following situation:


*[illustration CantProveMidPoint.jpg]


The measure of AC is 4 units and the measure of AB is 2 units.  2 times 2 is certainly 4, but B is certainly not the midpoint of AC.


Now if you had bothered to mention that B was located on the line segment AC, that would have been a different story.  But that isn't what you asked, is it?


Extra credit:  Why would it have been insufficient to state that A, B, and C are collinear?


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it

*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \