Question 986485
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According to the Fundamental Theorem of Algebra, the number of zeros of a polynomial function is equal to the degree of the function.


Rational zeros can be singular, but irrational and complex zeros always appear as conjugate pairs.  Hence if *[tex \Large a\ +\ bi] is a zero, even if the value of the real part is zero, then the conjugate, *[tex \Large a\ -\ bi], must be a zero as well.


You were given one rational zero and two complex zeros that are NOT conjugates of each other.  So how many do you count?


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it

*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \