Question 986483
Slope of line BC is  {{{(10-9)/(-7-(-4))=-1/3}}}.


The line perpendicular to line BC must have the slope {{{m=3}}} and pass through A(6,0).  In point-slope equation form, this is {{{highlight(y-0=3(x-6))}}} or {{{highlight(highlight_green(y=3(x-6)))}}}.