Question 84277
get y on the right side
y<3/2-x/2
y>-2+2x/3
now to find points for first line pretend x=0, put it in then you get y=3/2, ignore inequalities for now. then say x=1 then y = 1
graph a line from those two points, this will be your read line
same for second equation, say x=0 then y=-2 say x= 6 then y =2
graph a line from those two points, this will be your green line
{{{ graph( 300, 300, -7, 7, -7, 7, 3/2-x/2, -2+(2x)/3) }}} 
you aren't done yet :) now you have to look at inequalities, for the red line y is less than, so the solution lies below red line (shade averything below red line), also for green line y is more than so everything above green line (shade everything above green line). Now where the shading overlaps, that's the solution :) 
PS make sure you draw your lines  like this - - - -  not a solid line. If your equation was <or= then you would draw a solid line and it also means that the solutions would also lie on that line. But not in our case :)