Question 986402
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The coefficient on the *[tex \Large x^{n\,-\,k}y^{k}] term in the expansion of *[tex \Large (x\ +\ y)^n] is the number of combinations of *[tex \Large n] things taken *[tex \Large k] at a time.


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ {{n}\choose{k}}\ =\ \frac{n!}{k!(n\,-\,k)!}]


For your problem, *[tex \Large n\ =\ 8] and *[tex \Large n\ -\ k\ =\ 5], so you should be able to determine the *[tex \Large k] you need.  Just do the arithmetic.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it

*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \