Question 986399
This is an arithmetic sequence with common difference of d = 1. The first term is a = 34


Subtract the last term and first term to get: 103-34 = 69. Add on 1 to get 69+1 = 70. So there are 70 terms in the summation above. This means n = 70


We have these three values
a = 34
d = 1
n = 70


Plug them into the arithmetic sum formula. Doing all that will give you


{{{S[n] = (n*(2*a+d*(n-1)))/2}}}


{{{S[70] = (70*(2*34+1*(70-1)))/2}}}


{{{S[70] = 4795}}}


In the end, 34+35+36+37+...+102+103 = <font color="red">4,795</font>



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