Question 84313
If the question is

{{{((y-2)/(y+3)) - (y/(2y+6))}}} 
= {{{((2*(y-2))/(2*(y +3)))  - (y/(2y+6))}}} 
= {{{(2*(y-2)-y)/(2y+6)}}}
= {{{(y-4)/(2y+6)}}}