Question 84313
please start using parenthesis so we know where division begins and ends, the way you wrote it it could be viewed two different ways, noone wants to work harder than they have to ;)

if this is what you meant {{{(y-2)/(y+3) - y/(2y+6)}}}
then i got this

{{{(y-2)/(y+3) - y/(2(y+3))=(2y-4-y)/((2(y+3))=(y-4)/(2y+6)}}}