Question 986306
log2 (x+y)=3
x2-3y2=4
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{{{log(2,(x+y)) = 3}}} --> x+y = 8
y = 8-x
Sub for y in the 2nd equation.
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Use ^ (Shift 6) for exponents.
x^2 - 3y^2 = 4
{{{x^2 - 3(8-x)^2 = 4}}}