Question 986293
You are told the zeroes are -2, -3 and -1

So you know that x=-2 , x=-3 and x=-1 cause the polynomial to result in a zero answer. 

Thus
{{{(x+2)(x+3)(x+1) = 0 }}} is your starting point. Now, just expand it out
{{{(x^2 + 3x + 2x +6)(x+1) = 0}}}
{{{(x^2 + 5x + 6)(x+1) = 0 }}}
{{{x^3 + x^2 + 5x^2 + 5x +6x + 6 = 0}}}
{{{x^3 + 6x^2 + 11x + 6 = 0}}}