Question 986237
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After he went past the 3rd guard, he had 2.


Just before that he had given the 3rd guard 3, so before he did that he had 5.

Just before he had 5 he gave the 3rd guard half of what he had, so he must have had 10.


Before that he gave the 2nd guard 3...


and so on.  You can figure out the rest.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it

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