Question 986236
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In order to have a 90 average over 6 exams (the four he has done plus the two that the final is worth), then his total of all six scores must be 6 times 90 or more. Add up the scores he already has, subtract from 6 times 90, then divide by 2 to find the necessary score for the final.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it

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