Question 986185
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If the average of 7 matches is *[tex \Large x], then the total runs scored in the 7 matches must be *[tex \Large 7x].  Then the total runs scored in 8 matches has to be *[tex \Large 7x\ +\ 9], and the average for 8 matches is *[tex \Large \frac{7x\ +\ 9}{8}].  This average is one less than the 7 match average, so:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{7x\ +\ 9}{8}\ =\ x\ -\ 1]


Solve for *[tex \Large x]


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it