Question 985988
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In order to have a 90 or greater average on 5 tests, the sum of the scores of the 5 tests must be greater than or equal to 5 times 90.  Add the scores already obtained and subtract that sum from the required 5 times 90.  The result will be the minimum score required for a 90 average.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it