Question 986169
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Let *[tex \Large x] represent the distance Leanna ran <i>after</i> Tatiana started running.  Since Leanna had been running for 15 minutes (one-quarter hour) before Tatiana started, she was 3.6 times 0.25 = 0.9 miles ahead.


The amount of time that Tatiana ran until she passed Leanna is the same as the amount of time that Leanna ran starting at her head-start position.


The time that Tatiana ran until she passed Leanna is given by:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{x\ +\ 0.9}{3.9}]


The time that Leanna ran after Tatiana started is given by:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{x}{3.6}]


Set these two expressions for equal values equal to each other and solve for *[tex \Large x].  Then calculate *[tex \Large x\ +\ 0.9] to get your final answer.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it

*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \