<PRE><B>Question 986161</B>
Find the values of a, b, and c such that the equation y = ax2 + bx + c has ordered pair solutions (-1, -4), (2, -7) and (3, 0) 
this is just a pretest 
------
Form:: ax^2 + bx + c = y
Solve for a,b, and c using the 3 pairs::
a - b + c = -4
4a +2b + c = -7
9a +3b + c = 0
----------------------
Using any method you know solve for a, b, and c::
Ans::
a = 2 ; b = -3 ; c = -9
-----
Equation:
y = 2x^2 -3x - 9
======================
Cheers,
Stan H.
---------------</PRE>