Question 84293
B varies inversely as the square root of c. 
b  = {{{k/sqrt(c)}}}
If b = 1 when c = 16, find k:
1  = {{{k/sqrt(16)}}}
1  = {{{k/4}}}
k = 4
:
find b when c = 6.
b = {{{4/(sqrt(6))}}}