<PRE><B>Question 986110</B>
Suppose in USA 30% of the workers take public transportation daily. 
A. In a sample of 10 workers, what is the probability that exactly three workers take public transportation daily?
-----
Ans:: P(x=3) = 10C3*0.3^3*0.7^7 = binompdf(10,0.3,3) = 0.2668
-----------------------------
B. In a sample of 10 workers, what is the probability that at least three workers take public transportation daily?
Ans: P(3&lt;= x &lt;=10) = 1 - binomcdf(10,0.3,2) = 0.0028
-------------
Cheers,
Stan H.
------------</PRE>