Question 986095
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Completely factor the numerator.  If *[tex \Large x\ -\ 2] is a factor of the numerator, eliminate that factor from both numerator and denominator.  What is left is the equivalent expression.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it

*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \