Question 84262
6=3t^2+2t
3t^2+2t-6=0{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}} 
t(-2+-sqrt2^2-4*3*-6])/2*3
t=(-2+-sqrt4+72])/6
t=(-2+-sqrt76)/6
t=(-2+-8.7)/6
t=(-2+8.7)/6
t=6.7/6
t=1.1 answer.
t=(-2-8.7)/6
t=-10.7/6
t=-1.8 answer.