Question 986098
Hi dear,
if the straight line passes through the points (-2,1) and (3,-2) 
Then,the formula below will be used to solve for the equation of the line.
{{{(y-y[1])*(x[2]-x[1])=(x-x[1])*(y[2]-y[1])}}}
where y1=1,y2=-2,x1=-2,x2=3.
substitute the above in the given formula
Therefore,
(y-1)(3+2)=(x+2)(-2-1)
5(y-1)=-3(x+2)
5y-5=3x+6
5y=3x+11
{{{y=(3x+11)/5}}}