Question 986006
〖log〗_10 x+ 〖log〗_10 2= 〖log〗_10 10-〖log〗_10 1
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log(x) - log(2) = log(10) - log(1)
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log(x/2) = 1
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x/2 = 10
x = 20
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Cheers,
Stan H.
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