Question 985930
.
{{{3x^2}}} + {{{2x}}} - {{{4}}} = {{{0}}}


Apply the quadratic formula 


{{{x}}} = {{{(-2 +- sqrt(2^2-4*3*(-4)))/6}}} = {{{-2 +- sqrt(4+48))/6}}} = {{{(-2 +- sqrt(52))/6}}} = {{{(-1 +- sqrt(13))/3}}}.


{{{x[1]}}} = {{{(-1 + sqrt(13))/3}}},   {{{x[2]}}} = {{{(-1 - sqrt(13))/3}}}.


What is difficult in it?