Question 985923
Hello,


I re-write your equation as follows by placing parentheses according to the common sense. Is this what you need?


{{{2/(x-2)}}} = {{{(x+2)/x}}}.


<B>Solution</B>


2x = (x-2)*(x+2),


{{{2x}}} = {{{x^2}}} - {{{4}}}


{{{x^2}}} - {{{2x}}} - {{{4}}} = {{{0}}},


{{{x[1]}}} = {{{1 + sqrt(5)}}}, &nbsp;&nbsp;{{{x[2]}}} = {{{1 - sqrt(5)}}}


(use the quadratic formula).