Question 985798
2ps^2= 3qs^2 + 5p make s the subject of the formula
2ps^2 - 3qs^2 = 5p
s^2*(2p - 3q) = 5p
s^2 = 5p/(2p - 3q)
{{{s = sqrt(5p/(2p-3q))}}}
Or,
{{{s = sqrt(5p*(2p-3q))/(2p-3q)}}}