Question 985744
</i>Perpendicular to y= 3x - 2</i>


The equation would be something as {{{y=-(1/3)x+b}}}.



<i>Passes through (6, -1)</i>


{{{y=mx+b}}}
{{{y-mx=mx+b-mx}}}
{{{y-mx=b}}}
{{{b=y-mx}}}
-
{{{b=-1-(-1/3)*6}}}
{{{b=-1+2}}}
{{{b=1}}}
Line you want is {{{highlight(y=-(1/3)x+1)}}}.