Question 985737
y=x^2+1
I need to find whether the graph opens up, or opens down, find the vertex, and the axis of symmetry. Please help... 8'(
<pre>{{{y = x^2 + 1}}} opens UPWARD, as the coefficient of {{{x^2}}} is > 0.
x-coordinate of vertex/Axis of symmetry: {{{- b/(2a)}}}, or {{{- 0/(2a)}}}, or {{{highlight_green(0)}}}
y-coordinate of vertex: {{{y = (0)^2 + 1}}}, or 1
Vertex: ({{{0}}}{{{","}}}{{{1}}})