Question 985594
Find all solutions of the equation in the interval [0,2π).


{{{ 4cos^2(x)=5 - 4 sin(x) }}}
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Sub 1 - sin^2 for cos^2, then it's a quadratic.
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4 - 4sin^2 = 5 - 4sin
4sin^2 - 4sin + 1 = 0
*[invoke solve_quadratic_equation 4,-4,1]
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sin(x) = 1/2
x = pi/6, 5pi/6