<PRE><B>Question 985460</B>

&lt;B&gt;Answer&lt;/B&gt;. &amp;nbsp;90°.


&lt;B&gt;Solution&lt;/B&gt;


Since &amp;nbsp;&lt;B&gt;AB&lt;/B&gt;&amp;nbsp; is twice the radius of the circle, &amp;nbsp;&lt;B&gt;AB&lt;/B&gt;&amp;nbsp; is the diameter of the circle.


The angle &amp;nbsp;&lt;I&gt;L&lt;/I&gt;&lt;B&gt;ACB&lt;/B&gt;&amp;nbsp; is &amp;nbsp;90°, &amp;nbsp;because it leans on the diameter.


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