Question 985203
y = h − 16t^2 , where y is the height of the object, t is the number of seconds the object has been falling, and h is the height from which the object was dropped
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a) y = 555 - 16(2^2)
y = 555 - 64 = 491,
--the iron ball is 491 feet above the ground after 2 seconds
0 = 555 - 16t^2
16t^2 = 555
t^2 = 555 / 16
t = square root(555 / 16) = square root(555) / 4 = 5.889609495 approx 5.9
--it takes 5.9 seconds for the iron ball to hit the ground
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b)  y = h − 2.5t^2, 555/2 = 277.5
set equations a and b equal to each other
555 - 16t^2 = 277.5 - 2.5t^2
13.5t^2 = 277.5
t^2 = 277.5 / 13.5 = 20.555555556
t = square root(20.555555556) = 4.533823503
--in 4.5 seconds the ball will overtake the bag of chips
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c) y = 555 - 16t^2 (red line), y = 277.5 - 2.5t^2 (green line)
{{{ graph( 300, 200, -30, 30, -600, 600, 555 - 16*x^2, 277.5 - 2.5*x^2) }}}
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calculate y intercept by setting t = 0
calculate t intercept by setting y = 0
--y = 555 - 16t^2
y intercept is (555, 0)
--0 = 555 - 16t^2
t = 5.9
t intercept is (0, 5.9)
--y = 277.5 - 2.5t^2
y intercept is (277.5, 0)
--0 = 277.5 - 2.5t^2
t = 10.535653753 approx 10.5
t intercept is (0, 10.5)
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--y intercept is the height above the ground, t intercept is the time in seconds it takes the object to reach the ground
--the intersection point gives us the height above the ground when the objects over take each other and the time it takes for that to happen