Question 985341
{{{x - (3/x) + 1 >= 0}}}
{{{(x^2 -3+x)/x  >= 0}}}
{{{x^2 + x - 3 >= 0}}}

Now find the zeros for the equality {{{x^2 + x - 3 = 0}}}
*[invoke quadratic "x", 1, 1, -3 ]

Using the graph above, you see that when x is less than or equal to -2.3 or greater than equal t0 1.3 , the equation is satisfied