Question 985336
x^2 -2ax +a^2-b^2
the form for the quadratic equation is 
ax^2 + bx + c, therefore
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for this problem
a = 1
b = -2a
c = a^2-b^2
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x = (-b + or - square root(b^2 - 4ac)) / 2a
for this problem
x = (-(-2a) + square root( (-2a)^2 - 4 * (1) * (a^2 - b^2) ) ) / 2 
x = ( 2a + square root( 4a^2 - 4a^2 + 4b^2) ) / 2
x = ( 2a + 2b) / 2
x = (a + b)
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x = (2a - 2b) / 2
x = (a - b)
therefore the factors are
(x - (a+b))  and (x - (a-b))