Question 985279
{{{2=(-3+b)^2+c}}}
{{{(b-3)^2+c=2}}}
{{{b^2-6b+9-2+c=0}}}
{{{b^2-6b+c=-7}}}


{{{11=(0+b)^2+c}}}
{{{b^2+c=11}}}
and use this to find c in terms of b.
{{{c=11-b^2}}}
and substitute this into the other equation.


{{{b^2-6b+11-b^2=-7}}}
{{{-6b+11=-7}}}
{{{-6b=-18}}}
{{{highlight(b=3)}}}-----------and you can find c on your own from here.