<PRE><B>Question 985255</B>
How do you solve {{{ 6 -(5/(x+1)) = (6/(x-3))}}}

I have tried this problem, but I go nowhere. 

{{{(6x+6-5)/(x+1)  =  -6/(x-3)}}} *** This is OK, except you changed the RHS to negative.
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{{{(6x+6-5)/(x+1)  =  6/(x-3)}}}
{{{(6x+1)/(x+1)  =  6/(x-3)}}}
Cross multiply
6(x+1) = (6x+1)*(x-3)
{{{6x + 6 = 6x^2 - 17x - 3}}}
{{{6x^2 - 23x - 9 = 0}}}
*[invoke solve_quadratic_equation 6,-23,-9]



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