Question 84166
The area of a square is :
{{{4p^2-4p+1}}}sq.in.
Find the length of the side of the square.
The area of a square is given by:
{{{A = s^2}}} where s is the length of the side of the square.
In this problem, you are given:
{{{A = 4p^2-4p+1}}} so...
{{{s^2 = 4p^2-4p+1}}} Factor the trinomial.
{{{s^2 = (2p-1)(2p-1)}}} or {{{(2p-1)^2}}} Take the square root of both sides.
{{{s = 2p-1}}}in.  This is the length of the side of the square!