Question 985158
In equilateral
 angle p+ angle q+angle r+ angle s=360
 p+q+r+s=360
p=3q
 r=4s
s=q
so r=4q
3q+q+4q+q=360
9q=360
  q=360/9
 q=40
 p=3*40
 = 120
r=4*40
 =160
s=q=40
Result : angle  p=120
   angle q=40
angle r =160
angle s=40